When feeder circuits are routed over long distances (when you get close to a
100 feet run from power source to the load), then you have a voltage drop that
you need to account for. All wires present a certain amount of resistance to the
current going through them, and if you increase the amount of wire (longer run)
then you're increasing the overall resistance through that circuit.
In order to
prevent damage to the equipment or wire, you need to increase the size of the
wire (diameter) to decrease or eliminate the voltage drop. The amount of voltage
drop usually allowed per NEC is up to 3 % for branch circuits, and 5 % for the
overall voltage drop (from the power source to the farthest outlet).
This falls above the 3 % max. allowed, so you would check to see if you can
use a # 4 THWN copper. (check NEC Chapter 9 Table 8 - Conductor Properties -
column- ohm / kft = 0.308)
Do the same as the above example,
substituting the resistivity value for # 4 copper, and if the VD falls under the
permitted 3 % range then use it!
Example (2) using VD = (2 * L * K * I) /
CM
Find the voltage drop on a # 4 THWN copper, 3 wire, 120/240 Volt,
single phase feeder circuit of 200 foot length having a 50 A load.
Use the
formula above, and substitute the given values.
Use 12 for the resistivity constant for copper
VD = (2 * 200' * 12 * 50) / 41740 = 5.75 Volts
The voltage drop is 5.75
Volts, we now have to check the % from the overall voltage.
This falls under the 3 % max. allowed, so you can use it!
Calculating
Voltage Drop - 3 Phase
When calculating the voltage drop in 3 phase circuits, do the same as in the
single phase but the voltage drop must be multiplied by 0.866. Basically the
voltage drop between any two phases conductors is multiplied by (1.732 / 2) =
0.866.
Example
Find the voltage drop and size THWN copper, 120/208
Volt, 3 phase feeder circuit of 200 foot length having a 150 Amp load.
Try 3/O
copper with resistivity of 0.0766
Step (1)
VD = (2 * L * R * I ) / 1000 ft = (2 * 200 * 0.0766 * 150) / 1000 ft = 4.596
VD
Step (2) as per 215-2(b)
VD = 4.596 * .866 = 3.98
Step (3)
208 Volts * 3 % = 6.24 Volts (max. allowed)
So, the VD = 3.98 Volts which is below the 6.24 Volts allowed.
Even though this size wire would work, try the next lower size wire to see if
that would also work.
The reason is that if you can do the job with a smaller size wire, it will
cost you less in supplies and leave you with more profit. (Check the 2/0
copper!)